tag:blogger.com,1999:blog-28687371.post-442190498244039532008-01-15T11:46:00.000-08:002008-01-15T11:46:00.000-08:002008-01-15T11:46:00.000-08:00Ahhh, but it's even better than P/Cs - assuming th...Ahhh, but it's even better than P/Cs - assuming the encryption algorithm is approaching a uniform cyphertext distribution (which is the goal of most cryptosystems), then the EXPECTED crack time is equal to P/2(Cs).Kurthttp://www.blogger.com/profile/09031183881458956190noreply@blogger.com